f(a+9)=4x^2+2x-5

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Solution for f(a+9)=4x^2+2x-5 equation:


Simplifying
f(a + 9) = 4x2 + 2x + -5

Reorder the terms:
f(9 + a) = 4x2 + 2x + -5
(9 * f + a * f) = 4x2 + 2x + -5

Reorder the terms:
(af + 9f) = 4x2 + 2x + -5
(af + 9f) = 4x2 + 2x + -5

Reorder the terms:
af + 9f = -5 + 2x + 4x2

Solving
af + 9f = -5 + 2x + 4x2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-9f' to each side of the equation.
af + 9f + -9f = -5 + 2x + -9f + 4x2

Combine like terms: 9f + -9f = 0
af + 0 = -5 + 2x + -9f + 4x2
af = -5 + 2x + -9f + 4x2

Reorder the terms:
af = -5 + -9f + 2x + 4x2

Divide each side by 'f'.
a = -5f-1 + -9 + 2f-1x + 4f-1x2

Simplifying
a = -5f-1 + -9 + 2f-1x + 4f-1x2

Reorder the terms:
a = -9 + -5f-1 + 2f-1x + 4f-1x2

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